Original Price 3

harpazo

Pure Mathematics
An item sells for $300.00 after a 20% discount. Find the original price.
 

anemone

Paris la ville de l'amour
Math Helper

MarkFL

La Villa Strangiato
Math Helper
I would let \(P\) be the original price, \(D\) be the portion added/subtracted, and \(R\) be the retail price. Then we can state:

[MATH]P(1+D)=R[/MATH]
Hence:

[MATH]P=\frac{R}{D+1}[/MATH]
Now we have a general formula for all such problems. Applying it to this one, we identify:

[MATH]R=300,\,D=-0.2[/MATH]
Thus:

[MATH]P=\frac{300}{-0.2+1}=\frac{300}{\dfrac{4}{5}}=5\cdot\frac{300}{4}=5\cdot75=375[/MATH]
 

harpazo

Pure Mathematics
I would let \(P\) be the original price, \(D\) be the portion added/subtracted, and \(R\) be the retail price. Then we can state:

[MATH]P(1+D)=R[/MATH]
Hence:

[MATH]P=\frac{R}{D+1}[/MATH]
Now we have a general formula for all such problems. Applying it to this one, we identify:

[MATH]R=300,\,D=-0.2[/MATH]
Thus:

[MATH]P=\frac{300}{-0.2+1}=\frac{300}{\dfrac{4}{5}}=5\cdot\frac{300}{4}=5\cdot75=375[/MATH]

I enjoy your ability to create a general formulas for problems. Wish I had such talent back in my college days.
 

anemone

Paris la ville de l'amour
Math Helper
@harpazo, please post new question only after you have replied to your previous countless threads, and please don't let Mark to finish up for you. Thanks.

I would let \(P\) be the original price, \(D\) be the portion added/subtracted, and \(R\) be the retail price. Then we can state:

[MATH]P(1+D)=R[/MATH]
Hence:

[MATH]P=\frac{R}{D+1}[/MATH]
Now we have a general formula for all such problems. Applying it to this one, we identify:

[MATH]R=300,\,D=-0.2[/MATH]
Thus:

[MATH]P=\frac{300}{-0.2+1}=\frac{300}{\dfrac{4}{5}}=5\cdot\frac{300}{4}=5\cdot75=375[/MATH]

Nicely done, Mark!(Happy)
 

harpazo

Pure Mathematics
@harpazo, please post new question only after you have replied to your previous countless threads, and please don't let Mark to finish up for you. Thanks.



Nicely done, Mark!(Happy)

I occassionally overload the site with math questions for two reasons:

1. To give members extra practice.

2. To increase the popularity of the site.

I have been reviewing trigonometry for a few months and Mark is my online tutor for this purpose.
 
Last edited:

MarkFL

La Villa Strangiato
Math Helper
Please do not use insulting language towards anemone. I don't mind if you disagree, but please do so civilly. She and I are very close, and I won't take kindly to insulting language being directed her way. I would have been fine with your post were it not for the remark about her not reading well (she is fluent in 6 languages) and the demanding tone that she stay out of your threads. That's not necessary and I will not have her spoken to like that. Behind the scenes she takes the brunt of my complaints about problems not being followed up and my follow-up questions largely being ignored, so she's just trying to look out for me. Notice she did not use personally insulting language in any of her posts.

I should look into creating a thread prefix that can be added to practice questions so we can easily spot which are practice and which aren't.
 

harpazo

Pure Mathematics
100% - 20% = 80%

(100/80) × 300 = 375

Original price = $375
 
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