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- Thread starter puremath
- Start date

A. It looks like \(f\) is defined to be a function of 1 variable, so treating it like a function of two variables makes no sense.

B. Give this a go...you should be able to show that it is zero.

I edited A. This looks like composition of functions.

Ok.Adding the argument, we find it is:

[MATH]f(\pi)=0[/MATH]