Addition of Fractions 1

harpazo

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TheJason

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\(\displaystyle \dfrac{1}{a} + \dfrac{1}{b}\)

\(\displaystyle \dfrac{(1)(b) + (a)(1)}{(a)(b)} = \dfrac{b + a}{ab}\)
 

harpazo

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\(\displaystyle \dfrac{1}{a} + \dfrac{1}{b}\)

\(\displaystyle \dfrac{(1)(b) + (a)(1)}{(a)(b)} = \dfrac{b + a}{ab}\)
The answer can also be expressed as

(a + b)/(ab).