Addition of Fractions 1

[harpazo]

 

[TheJason]

\(\displaystyle \dfrac{1}{a} + \dfrac{1}{b}\)

\(\displaystyle \dfrac{(1)(b) + (a)(1)}{(a)(b)} = \dfrac{b + a}{ab}\)

 

[harpazo]

\(\displaystyle \dfrac{1}{a} + \dfrac{1}{b}\)

\(\displaystyle \dfrac{(1)(b) + (a)(1)}{(a)(b)} = \dfrac{b + a}{ab}\)

The answer can also be expressed as

(a + b)/(ab).