What's a good strategy for finding the angle for each quadrant? @MarkFL Thanks.

Jason Administrator Staff member Administrator Moderator Jan 25, 2018 2,521 547 113 jasonyankee.info May 18, 2019 #1 What's a good strategy for finding the angle for each quadrant? @MarkFL Thanks.

MarkFL La Villa Strangiato Staff member Administrator Moderator Math Helper Jan 25, 2018 3,573 4,322 113 St. Augustine May 18, 2019 #2 Can you give an example?

Jason Administrator Staff member Administrator Moderator Jan 25, 2018 2,521 547 113 jasonyankee.info May 18, 2019 #3 MarkFL said: Can you give an example? Click to expand... (a.) Find the vector components of 95 degrees with a magnitude of 350 m. Last edited: May 18, 2019

MarkFL said: Can you give an example? Click to expand... (a.) Find the vector components of 95 degrees with a magnitude of 350 m.

MarkFL La Villa Strangiato Staff member Administrator Moderator Math Helper Jan 25, 2018 3,573 4,322 113 St. Augustine May 18, 2019 #4 I would write something like: \(\displaystyle v_x=350\cos\left(95^{\circ}\right)\) \(\displaystyle v_y=350\sin\left(95^{\circ}\right)\) Reactions: anemone and Jason

I would write something like: \(\displaystyle v_x=350\cos\left(95^{\circ}\right)\) \(\displaystyle v_y=350\sin\left(95^{\circ}\right)\)

Jason Administrator Staff member Administrator Moderator Jan 25, 2018 2,521 547 113 jasonyankee.info May 19, 2019 #5 MarkFL said: I would write something like: \(\displaystyle v_x=350\cos\left(95^{\circ}\right)\) \(\displaystyle v_y=350\sin\left(95^{\circ}\right)\) Click to expand... How about for negative angles (any quadrant) or positive ones in the 3rd and 4th quadrants?

MarkFL said: I would write something like: \(\displaystyle v_x=350\cos\left(95^{\circ}\right)\) \(\displaystyle v_y=350\sin\left(95^{\circ}\right)\) Click to expand... How about for negative angles (any quadrant) or positive ones in the 3rd and 4th quadrants?

MarkFL La Villa Strangiato Staff member Administrator Moderator Math Helper Jan 25, 2018 3,573 4,322 113 St. Augustine May 19, 2019 #6 You could use \(0\le\theta<2\pi\) or \(-\pi\le\theta<\pi\). Reactions: anemone