If x = 7, evaluate f(x) = -sqrt{2 +x}.

harpazo Pure Mathematics Mar 20, 2018 5,788 361 83 NYC Jul 6, 2018 #1 If x = 7, evaluate f(x) = -sqrt{2 +x}. Reactions: MarkFL

Jason Administrator Staff member Administrator Moderator Jan 25, 2018 2,521 547 113 jasonyankee.info Jul 7, 2018 #2 If \(\displaystyle x = 7\), evaluate \(\displaystyle f(x) = -\sqrt{2 +x}\). Just plug and chug: \(\displaystyle f(7) = -\sqrt{2 + (7)}\). \(\displaystyle f(7) = -\sqrt{9}\). \(\displaystyle f(7) = -3\). Last edited: Jul 7, 2018 Reactions: harpazo and MarkFL

If \(\displaystyle x = 7\), evaluate \(\displaystyle f(x) = -\sqrt{2 +x}\). Just plug and chug: \(\displaystyle f(7) = -\sqrt{2 + (7)}\). \(\displaystyle f(7) = -\sqrt{9}\). \(\displaystyle f(7) = -3\).

harpazo Pure Mathematics Mar 20, 2018 5,788 361 83 NYC Jul 7, 2018 #3 TheJason said: If \(\displaystyle x = 7\), evaluate \(\displaystyle f(x) = -\sqrt{2 +x}\). Just plug and chug: \(\displaystyle f(7) = -\sqrt{2 + (7)}\). \(\displaystyle f(7) = -\sqrt{9}\). \(\displaystyle f(7) = -3\). Click to expand... Very good.

TheJason said: If \(\displaystyle x = 7\), evaluate \(\displaystyle f(x) = -\sqrt{2 +x}\). Just plug and chug: \(\displaystyle f(7) = -\sqrt{2 + (7)}\). \(\displaystyle f(7) = -\sqrt{9}\). \(\displaystyle f(7) = -3\). Click to expand... Very good.