Practice Find S'(x) & C'(x)

Jan 15, 2020
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I know the quotient rule is used to find S'(x) and C'(x). Find S'(x) and C'(x). I will then find the following: S'(0) and C'(1).

20200211_033149.jpg
 

MarkFL

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We don't need the quotient rule, just the following rules:

\(\displaystyle y=k\cdot f(x)\implies y'=k\cdot f'(x)\)

\(\displaystyle y=e^{f(x)}\implies y'=e^{f(x)}\cdot f'(x)\)

You should be able to show:

\(\displaystyle \frac{d}{dx}\sinh(x)=\cosh(x)\)

\(\displaystyle \frac{d}{dx}\cosh(x)=\sinh(x)\)
 
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Jan 15, 2020
659
7
18
54
Bronx, NY
We don't need the quotient rule, just the following rules:

\(\displaystyle y=k\cdot f(x)\implies y'=k\cdot f'(x)\)

\(\displaystyle y=e^{f(x)}\implies y'=e^{f(x)}\cdot f'(x)\)

You should be able to show:

\(\displaystyle \frac{d}{dx}\sinh(x)=\cosh(x)\)

\(\displaystyle \frac{d}{dx}\cosh(x)=\sinh(x)\)
I surely will follow-up on this problem. I want to do the math and then evaluate the derivative for each function. I am not in calculus yet but there are derivatives and some integration questions that I can do even now. Going to bed.

P. S. I know you hate me for saying this will be done at a later time but I want to do the work, right or wrong as a follow-up.
 
Jan 15, 2020
659
7
18
54
Bronx, NY
We don't need the quotient rule, just the following rules:

\(\displaystyle y=k\cdot f(x)\implies y'=k\cdot f'(x)\)

\(\displaystyle y=e^{f(x)}\implies y'=e^{f(x)}\cdot f'(x)\)

You should be able to show:

\(\displaystyle \frac{d}{dx}\sinh(x)=\cosh(x)\)

\(\displaystyle \frac{d}{dx}\cosh(x)=\sinh(x)\)
20200214_115719.jpg


20200214_115733.jpg
 

MarkFL

La Villa Strangiato
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Jan 25, 2018
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Yes, good work! :)
 
Jan 15, 2020
659
7
18
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Bronx, NY
Yes, good work! :)
I know just the basics of Calculus 1 and 2, just the basics. When we get there after Cohen, I want to dive deep into calculus, maybe even 4 or 5 limits using delta and epsilon. There is a sleep over event at the job. I requested tonight off two weeks ago.
 

MarkFL

La Villa Strangiato
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Since \(\displaystyle \sinh'(x)=\cosh(x)\), yes.
 
Jan 15, 2020
659
7
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Bronx, NY
Since \(\displaystyle \sinh'(x)=\cosh(x)\), yes.
Using W/A, cosh(0) = 1.

sinh(1) is a transcendental number whose value is (e^2 - 1)/(2e).