\int\,u\,d(v) = u\,v\, - \int\,v\,d(u) How to choose which one is u and which one is v?

Jason Administrator Staff member Administrator Moderator Jan 25, 2018 2,521 547 113 jasonyankee.info Nov 15, 2018 #1 \(\displaystyle \int\,u\,d(v) = u\,v\, - \int\,v\,d(u)\) How to choose which one is \(\displaystyle u\) and which one is \(\displaystyle v\)?

\(\displaystyle \int\,u\,d(v) = u\,v\, - \int\,v\,d(u)\) How to choose which one is \(\displaystyle u\) and which one is \(\displaystyle v\)?

MarkFL La Villa Strangiato Staff member Administrator Moderator Math Helper Jan 25, 2018 3,573 4,322 113 St. Augustine Nov 15, 2018 #2 I generally follow the LIATE rule for choosing which will be \(u\), and which will be \(v\,du\). Integration by parts - Wikipedia Reactions: anemone

I generally follow the LIATE rule for choosing which will be \(u\), and which will be \(v\,du\). Integration by parts - Wikipedia

Jason Administrator Staff member Administrator Moderator Jan 25, 2018 2,521 547 113 jasonyankee.info Nov 15, 2018 #3 MarkFL said: I generally follow the LIATE rule for choosing which will be \(u\), and which will be \(v\,du\). Integration by parts - Wikipedia Click to expand... Yeah, I recall that one now.

MarkFL said: I generally follow the LIATE rule for choosing which will be \(u\), and which will be \(v\,du\). Integration by parts - Wikipedia Click to expand... Yeah, I recall that one now.