Simplify

harpazo

Pure Mathematics
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Mar 20, 2018
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361
83
NYC
Simplify

sDraw_2018-07-21_22-39-19.png
 

TheJason

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\(\displaystyle \dfrac{3}{5b} - \dfrac{2}{4b} + \dfrac{1}{7c} + \dfrac{7}{21c}\)

\(\displaystyle \dfrac{-2}{4b} + \dfrac{1}{7c}\)

\(\displaystyle \dfrac{(-2)(7c) + (4b)(1)}{(4b)(7c)} = \dfrac{(-2)(7c)}{(4b)(7c)} + \dfrac{(4b)(1)}{(4b)(7c)}\)

Cancel out stuff.

\(\displaystyle \dfrac{-2}{4b} + \dfrac{1}{7c}\)

\(\displaystyle \dfrac{3}{5b} -\dfrac{2}{4b} + \dfrac{1}{7c}+ \dfrac{7}{21c}\)

in progress
 
Last edited:

harpazo

Pure Mathematics
Banned
Mar 20, 2018
5,788
361
83
NYC
\(\displaystyle \dfrac{3}{5b} - \dfrac{2}{4b} + \dfrac{1}{7c} + \dfrac{7}{21c}\)

\(\displaystyle \dfrac{-2}{4b} + \dfrac{1}{7c}\)

\(\displaystyle \dfrac{(-2)(7c) + (4b)(1)}{(4b)(7c)} = \dfrac{(-2)(7c)}{(4b)(7c)} + \dfrac{(4b)(1)}{(4b)(7c)}\)

Cancel out stuff.

\(\displaystyle \dfrac{-2}{4b} + \dfrac{1}{7c}\)

\(\displaystyle \dfrac{3}{5b} -\dfrac{2}{4b} + \dfrac{1}{7c}+ \dfrac{7}{21c}\)

in progress
Finish the problem.