Subtracting Fractions 2

harpazo

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TheJason

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\(\displaystyle \dfrac{2b}{10} - \dfrac{3t}{50x}\)

\(\displaystyle \dfrac{(2b)(50x) - (10)(3t)}{(10)(50x)} = \dfrac{(2b)(50x)}{(10)(50x)} - \dfrac{(10)(3t)}{(10)(50x)}\)

Cancel out stuff.

\(\displaystyle \dfrac{2b}{10} - \dfrac{3t}{50x}\)
 

harpazo

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\(\displaystyle \dfrac{2b}{10} - \dfrac{3t}{50x}\)

\(\displaystyle \dfrac{(2b)(50x) - (10)(3t)}{(10)(50x)} = \dfrac{(2b)(50x)}{(10)(50x)} - \dfrac{(10)(3t)}{(10)(50x)}\)

Cancel out stuff.

\(\displaystyle \dfrac{2b}{10} - \dfrac{3t}{50x}\)
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MarkFL

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\(\displaystyle \frac{2b}{10}-\frac{3t}{50x}=\frac{b}{5}\cdot\frac{10x}{10x}-\frac{3t}{50x}=\frac{10bx-3t}{50x}\)
 
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harpazo

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\(\displaystyle \frac{2b}{10}-\frac{3t}{50x}=\frac{b}{5}\cdot\frac{10x}{10x}-\frac{3t}{50x}=\frac{10bx-3t}{50x}\)
Very good.
 

TheJason

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OK, I get it. I didn't go far enough. My answer was another fraction subtraction situation!
 

harpazo

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harpazo

Pure Mathematics
Banned
Mar 20, 2018
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361
83
NYC